Optimal. Leaf size=110 \[ b \text{Unintegrable}\left (\frac{\tan ^{-1}(c x) \left (d+e x^2\right )^{5/2}}{x^2},x\right )+\frac{15}{8} a d^2 \sqrt{e} \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )-\frac{a \left (d+e x^2\right )^{5/2}}{x}+\frac{5}{4} a e x \left (d+e x^2\right )^{3/2}+\frac{15}{8} a d e x \sqrt{d+e x^2} \]
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Rubi [A] time = 0.186994, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x^2} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int \frac{\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x^2} \, dx &=a \int \frac{\left (d+e x^2\right )^{5/2}}{x^2} \, dx+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx\\ &=-\frac{a \left (d+e x^2\right )^{5/2}}{x}+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx+(5 a e) \int \left (d+e x^2\right )^{3/2} \, dx\\ &=\frac{5}{4} a e x \left (d+e x^2\right )^{3/2}-\frac{a \left (d+e x^2\right )^{5/2}}{x}+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx+\frac{1}{4} (15 a d e) \int \sqrt{d+e x^2} \, dx\\ &=\frac{15}{8} a d e x \sqrt{d+e x^2}+\frac{5}{4} a e x \left (d+e x^2\right )^{3/2}-\frac{a \left (d+e x^2\right )^{5/2}}{x}+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx+\frac{1}{8} \left (15 a d^2 e\right ) \int \frac{1}{\sqrt{d+e x^2}} \, dx\\ &=\frac{15}{8} a d e x \sqrt{d+e x^2}+\frac{5}{4} a e x \left (d+e x^2\right )^{3/2}-\frac{a \left (d+e x^2\right )^{5/2}}{x}+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx+\frac{1}{8} \left (15 a d^2 e\right ) \operatorname{Subst}\left (\int \frac{1}{1-e x^2} \, dx,x,\frac{x}{\sqrt{d+e x^2}}\right )\\ &=\frac{15}{8} a d e x \sqrt{d+e x^2}+\frac{5}{4} a e x \left (d+e x^2\right )^{3/2}-\frac{a \left (d+e x^2\right )^{5/2}}{x}+\frac{15}{8} a d^2 \sqrt{e} \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )+b \int \frac{\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x^2} \, dx\\ \end{align*}
Mathematica [A] time = 9.01508, size = 0, normalized size = 0. \[ \int \frac{\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x^2} \, dx \]
Verification is Not applicable to the result.
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Maple [A] time = 0.585, size = 0, normalized size = 0. \begin{align*} \int{\frac{a+b\arctan \left ( cx \right ) }{{x}^{2}} \left ( e{x}^{2}+d \right ) ^{{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (a e^{2} x^{4} + 2 \, a d e x^{2} + a d^{2} +{\left (b e^{2} x^{4} + 2 \, b d e x^{2} + b d^{2}\right )} \arctan \left (c x\right )\right )} \sqrt{e x^{2} + d}}{x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{\frac{5}{2}}{\left (b \arctan \left (c x\right ) + a\right )}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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